Question

what will be the least possible number of planks if 3 pieces of timber 42 metre 49 and 63 have to be divided into the blanks of same length

Answer 1

Answer:

No of planks=22

Step-by-step explanation:

factors of 42,49 and 63 are:

42=2*3*7

49=7*7

63=3*3*7

HCF( 42,49,63)=7

Hence length of plank=7 m

Total length of  three timber pieces:

42+49+63

=154

No of planks=154/7=22