Question

what will be the least possible number of planks if three pieces of timber 42m,49m and 63m long have to be dividend into planks of the same length?

Answer 1

Answer:

The least possible number of planks is 7 m.

Step-by-step explanation:

Given : If three pieces of timber 42 m, 49 m and 63 m long have to be dividend into planks of the same length.

To find : What will be the least possible number of planks?

Solution :

To find the least possible number which means the highest common factor of the numbers.

Prime factor of the numbers 42,49,63

$42=2\times 3\times 7$

$49=7\times 7$

$63=3\times 3\times 7$

The highest common factor of the numbers 42,49 and 63 is

$HCF=7$

Therefore, The least possible number of planks is 7 m.

Answer 2

Answer:

The least possible number of planks is 7 m.

Step-by-step explanation:

Given : If three pieces of timber 42 m, 49 m and 63 m long have to be dividend into planks of the same length.

To find : What will be the least possible number of planks?

Solution :

To find the least possible number which means the highest common factor of the numbers.

Prime factor of the numbers 42,49,63

The highest common factor of the numbers 42,49 and 63 is

Therefore, The least possible number of planks is 7 m.