Question

What will be the length of the hypotenuse of an isosceles right triangle whose side is 4√2 cm

1 point

12√2cm

12cm

8cm

8√2cm

​

Answer 1

Answer:

8 cm

Step-by-step explanation:

$= > {h}^{2} = 2 {(4 \sqrt{2}) }^{2} \\ = > {h}^{2} = 2 \times 16 \times 2 \\ = > {h} = \sqrt{ {2}^{2} \times 16 } \\ = >{h} = 8 \: cm$

Answer 2

Answer:

8 cm

Step-by-step explanation:

The hypotenuse is

$= \sqrt{ {(4 \sqrt{2}) }^{2} + {(4 \sqrt{2} })^{2} } = \sqrt{32 + 32}$

$= \sqrt{64} = 8 \: cm$