Question

What will be the length of the shadow of the tower when Vijay’s house casts a shadow of 12m? a. 75 m b. 50 m c. 45 m d. 60 m​

Answer 1

Answer:

50m

Step-by-step explanation:

50cm this is correct ans

Answer 2

Answer:

(a) Let the height of the tower is A’C’. We have AC = 20m & AB = 10m, And A’B’ = 50m & PQ = 20m. Hence, option (iii) is correct. (b) The height of Vijay’s house is AC = 20m. The height of the tower is A’C’ =100m. The length of shadow of Vijay’s house is AB = 12cm. Hence, option (iv) is correct. (c) AB = 10cm, AC = 20m, PQ = 20m. Let the height of Ajay’s house is PR. ∵ ABC & ΔPQR are similar triangles. ∴ The height of Ajay’s house is 40m. Hence, option (ii) is correct. (d) The height of tower is A’C’= 100m. And the height of Ajay’s house is PR = 40m The length of shadow of tower is A’B’= 40m. The length of shadow of Ajay’s house is PQ. ∵ ΔA′B′C′ and ΔPQR are similar triangles. Hence, the length of shadow of Ajay’s house is 16m. Hence, option (i) is correct. (e) The height of Vijay’s house is AC = 20m. The length of shadow of the tower is A’B’= 40m. The height of tower is A’C’= 100m. The length of the shadow of Vijay ′ s house is AB. ∵ ΔABC & ΔA′B′C ′ are similar triangles ∴ The length of the shadow of Vijay ′ s house is 8m. Hence, option (iv) is correct.Read more on Sarthaks.com - https://www.sarthaks.com/1107773/vijay-trying-find-the-average-height-tower-near-house-using-properties-similar-triangles