what will be the length of the square inscribed in a circle of radius 5cm?
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Answer:
Step-by-step explanation:
ABCD is a square inscribed in a circle of radius 5 cm.
Now, joining the diagonals of the square we get
The diagonals intersect at E. We know that the diagonals of square are perpendicular to each other.
In ∆AED, using Pythagoras Theorem,
AD^2 = DE^2 + AE^2
DE and EA are the radius of the circle, ∴ DE = EA
AD^2 = 2DE^2
AD^2 = 2 × 5^2 = 2 × 25 = 50
AD^2 = 50
AD^2 = 125
AD = √50 = 5√2 cm
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