what will be the loss of weight of a stone which weighs 1.5N in air when it dipped in kerosene
Answers
Answer:
To answer this question, I assume that the acceleration due to gravity where the stone was weighed is 9.8 m/s^2. Since its weight in air is 2.5 N it is equal to mg where m is the mass and g = 9.8m/s^2. Dividing 2.5 N by 9.8 m/s^2 will give its mass in kilogram. Its mass therefore is 2.5 N / 9.8 m/s^2 or 0.26 kg.
The relative density of kerosene is the apparent loss of weight in kerosene divided by its apparent loss of weight in water.
Solving for its apparent loss of weight in kerosene
apparent loss of weight = weight in air - weight in kerosene
apparent loss of weight = 2.5 N - 1.7 N = 0.8 N
Solving for its apparent loss of weight in water
apparent loss of weight = weight in air - weight in water
apparent loss of weight = 2.5 N -1.5 N = 1.0 N
Solving for the relative density of kerosene
relative density of kerosene = apparent loss of weight in kerosene / apparent loss of weight in water
relative density of kerosene = 0.8 N / 1.0 N
relative density of kerosene = 0.8
As a summary, the mass of the stone is 0.26 kg and the relative density of kerosene is 0.8.
To answer this question, I assume that the acceleration due to gravity where the stone was weighed is 9.8 m/s^2. Since its weight in air is 2.5 N it is equal to mg where m is the mass and g = 9.8m/s^2. Dividing 2.5 N by 9.8 m/s^2 will give its mass in kilogram. Its mass therefore is 2.5 N / 9.8 m/s^2 or 0.26 kg.
The relative density of kerosene is the apparent loss of weight in kerosene divided by its apparent loss of weight in water.
Solving for its apparent loss of weight in kerosene
apparent loss of weight = weight in air - weight in kerosene
apparent loss of weight = 2.5 N - 1.7 N = 0.8 N
Solving for its apparent loss of weight in water
apparent loss of weight = weight in air - weight in water
apparent loss of weight = 2.5 N -1.5 N = 1.0 N
Solving for the relative density of kerosene
relative density of kerosene = apparent loss of weight in kerosene / apparent loss of weight in water
relative density of kerosene = 0.8 N / 1.0 N
relative density of kerosene = 0.8
As a summary, the mass of the stone is 0.26 kg and the relative density of kerosene is 0.8.