Question

What will be the magnitude and the direction of acceleration of the stone when a stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed and if the stone makes 14 revolutions in 25 s?

Answer 1

Given :

length of string =1=80cm=80/100=0.8m

Number of revolutions=14
Time taken=t-25sec

Frequency is defined as number of revolution per given time
Frequency=n=14/25 Hz

Angular frequency=ω=2piν
=2x22/7x14/25
=88/25 rad/sec

Centripetal acceleration=ac=ω²r
=(88/25)² x 0.8
=(7744/625)x0.8
=12.39x0.8
=9.912 m/s2

The centripetal acceleration is always directed towards the centre at all points.

Answer 2

the answer is 9.912m square