Question

What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position? Farmer takes 40 s to move along the boundary.
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Bhai sanju ham dono ko chappal se maaregi ( ꈍᴗꈍ)​


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Answer 1

Explanation:

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Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

Answer 2

Answer:

Here, Side of the given square field = 10m

so, perimeter of a square = 4*side = 10 m * 4 = 40 m

Farmer takes 40 s to move along the boundary.

Displacement after 2 minutes 20 s = 2 * 60 s + 20 s = 140 seconds

since in 40 s farmer moves 40 m

Therefore, in 1s the distance covered by farmer = 40 / 40 m = 1m

Therefore, in 140s distance covered by farmer = 1 � 140 m = 140 m. Now, number of rotation to cover 140 along the boundary= Total Distance / Perimeter

= 140 m / 40 m = 3.5 round

Thus, after 3.5 round farmer will at point C of the field.

$therefore \: displacement \: ac = \\ \sqrt{( {10m}^{2} }) + ( { {10m}^{2} } ) \\ = \sqrt{ {100m}^{2} } + 100 {m}^{2} \\ \\ = \sqrt{ {200m}^{2} } \\ = 10 \sqrt{2} m \\ = 10 \times 1.141 \\ = 14.14m$

Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.