Question

What will be the mass of a 0.500m solution of sodium acetate?

Answer 1

Hello Dear.

Question is little bit incomplete. Question will be like this ⇒

What will be the mass of a 0.500 m solution of sodium acetate Solutions containing 2 mol of the sodium acetate. 

Solutions ⇒ 

Molality of the Solution = 0.5 m.
Number of moles of the solutes(or sodium acetate) = 0.15

Using the Formula,

Molality = No. of moles of the Solutes/Mass of the Solvent in kg.
Mass of the Solvent = 2/0.5
⇒ Mass of the Solvent = 4 kg.(or 4000 g).

Now,
No. of moles of the sodium acetate = 0.5 moles.
Molar Mass of the Sodium Acetate = 82 g/mol.

∵No. of moles = Mass/Molar Mass.
∴ Mass = No. of moles × Molar Mass.
⇒ Mass = 0.5 × 82
⇒ Mass = 41 g.

∵ Mass of the solution = Mass of the solute(or Sodium Acetate) + Mass of the Solvent.
∴ Mass of the solution = 4000 + 41
⇒ Mass of the Solution = 4041 g.
     = 4.041 kg.


Thus, Mass of the Solution is 4.041 kg.


[Note ⇒  The answer may be different, because I have assumed the Value of the No. of moles of Sodium Acetate as 2 moles, but may be in the book, the value may be different. Although, Method is totally Correct. Whatever may be the value you can substitute, you will get the exact answer.]



Hope it helps.

Answer 2

Explanation:

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