Physics, asked by manyakothari8686, 5 months ago

What will be the mass of an iron brick with dimensions 5 cm x 10 cm x 20 cm if the
density of iron is 8 g/cc? Find it in SI system of units also

Answers

Answered by AbhinavRocks10
2

Explanation:

Let P

1

,P

2

and P

3

be the pressures exerted by the brick while resting on different faces.

The dimensions of the given brick are 20cm×10cm×5cm

Case (i) : When the block is resting on 20cm×10cmface.

Thrust acting= Weight of the brick

T=500gwt

Area of constant (A)=20cm×10cm

Pressure exerted (P

1

)

=

Area

Thrust

=

20×10

500

∴P

1

=2.5gwtcm

−2

Case (ii) : When the block is resting on 20cm×5cmface

Thrust= Weight of the brick

=500gwt

Area of constant (A)=20cm×5cm

Pressure exerted

(P

2

)=

Area

Thrust

=

20×5

500

∴P

2

=5gwtcm

−2

  • Case (iii) : When the block on 10cm×5cmface
  • Thrust= Weight of the brick =500g.wt.
  • Area of contact =10cm×5cm

Pressure=

Area

Thrust

=

10×5

500

P

3

=10gwtcm

−2

∴ From the above three cases, it is clear that, as the area of contact decreases, the pressure exerted increases and is greater when the brick rests on its 10cm×5cm face.

HOPE IT WAS HELPFUL.▫️▪️❓

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
5

Given

  • Dimensions = 5 cm × 10 cm × 20 cm
  • Density = 8 g/c

To Find

  • Mass of the body

Solution

☯ Density = Mass/Volume

  • So here we have the density and the dimensions of the Brick so if we find the volume, then we can easily find the mass of the brick

☯ Volume = Length × Breath × Height

━━━━━━━━━━━━━━━━━━━━━━━━━

According to the Question :

→ Volume = Length × Breath × Height

  • Length = 20 cm
  • Breadth = 10 cm
  • Height = 5 cm

→ Volume = 20 × 10 × 5

→ Volume = 200 × 5

Volume = 1000 cm³

━━━━━━━━━━━━━━━━━━━━━━━━━

Mass of the Brick :

→ Density = Mass/Volume

→ 8 = Mass/1000

→ 8 × 1000 = Mass

→ Mass = 8000 kg

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