What will be the mass of an iron brick with dimensions 5 cm x 10 cm x 20 cm if the
density of iron is 8 g/cc? Find it in SI system of units also
Answers
Explanation:
Let P
1
,P
2
and P
3
be the pressures exerted by the brick while resting on different faces.
The dimensions of the given brick are 20cm×10cm×5cm
Case (i) : When the block is resting on 20cm×10cmface.
Thrust acting= Weight of the brick
T=500gwt
Area of constant (A)=20cm×10cm
Pressure exerted (P
1
)
=
Area
Thrust
=
20×10
500
∴P
1
=2.5gwtcm
−2
Case (ii) : When the block is resting on 20cm×5cmface
Thrust= Weight of the brick
=500gwt
Area of constant (A)=20cm×5cm
Pressure exerted
(P
2
)=
Area
Thrust
=
20×5
500
∴P
2
=5gwtcm
−2
- Case (iii) : When the block on 10cm×5cmface
- Thrust= Weight of the brick =500g.wt.
- Area of contact =10cm×5cm
Pressure=
Area
Thrust
=
10×5
500
P
3
=10gwtcm
−2
∴ From the above three cases, it is clear that, as the area of contact decreases, the pressure exerted increases and is greater when the brick rests on its 10cm×5cm face.
HOPE IT WAS HELPFUL.▫️▪️❓
Given
- Dimensions = 5 cm × 10 cm × 20 cm
- Density = 8 g/cm³
To Find
- Mass of the body
Solution
☯ Density = Mass/Volume
- So here we have the density and the dimensions of the Brick so if we find the volume, then we can easily find the mass of the brick
☯ Volume = Length × Breath × Height
━━━━━━━━━━━━━━━━━━━━━━━━━
✭ According to the Question :
→ Volume = Length × Breath × Height
- Length = 20 cm
- Breadth = 10 cm
- Height = 5 cm
→ Volume = 20 × 10 × 5
→ Volume = 200 × 5
→ Volume = 1000 cm³
━━━━━━━━━━━━━━━━━━━━━━━━━
✭ Mass of the Brick :
→ Density = Mass/Volume
→ 8 = Mass/1000
→ 8 × 1000 = Mass
→ Mass = 8000 kg