Question

What will be the maximum number of electrons present in an atom having n+l=5 in Cr=24​

Answer 1

Answer:

Given,

n + l = 4

where,

l = angular momentum quantum number

n = Principle quantum number

From Energy level of electrons we know,

l ≤ n - 1

Satisfying this condition,

The values of n and l will be 3,1 and 4,0 respectively.

Now:

Case I:

n = 3

l = 1

so, here these represents 3p subshell.

Hence, maximum no. of electrons = 6

Case II:

n = 4

l = 0

so, here these represents 4s subshell.

Hence, maximum no. of electrons = 2.

Therefore, from case I and II:

Total no. of electrons = 6 + 2 = 8

We know,

Electrons with same pin = 8 / 2 = 4

Explanation :

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Answer 2

Answer:

hence maximum number of electrons is equals to 2