Question

what will be the mean kinetic energy of one gram mole of a perfect gas at Absolute Temperature t​

Answer 1

Answer:

3/2RT ..............

Explanation:

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Answer 2

Mean kinetic energy of one gram mole of a perfect gas at absolute temperature T is  $\dfrac{3RT}{2}\ .$

We need to find the mean kinetic energy of one gram mole of a perfect gas at Absolute Temperature T .

We know according to Kinetic Theory Of Gases average kinetic energy associated with a particular direction is $\dfrac{RT}{2}\ .$

We know , their are the three dimensions associated to a particle is three times of a single direction .

Therefore , mean kinetic energy of one gram mole of a perfect gas at absolute temperature T is  $\dfrac{3RT}{2}\ .$

Hence , this is the required solution .

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