what will be the middle term of the quadratic equation in variable x whose roots are -5 and -4
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Answered by
18
Quadratic equation whose roots are ( -5 , -4) is
(x+5)(x+4) = 0 .
x²+5x+4x+20 = 0
x²+9x + 20 = 0 .
Middle term = 9x
Therefore, the middle term is 9x
(x+5)(x+4) = 0 .
x²+5x+4x+20 = 0
x²+9x + 20 = 0 .
Middle term = 9x
Therefore, the middle term is 9x
Answered by
10
Heya........!!!!
Given in the question :
➡ Roots of the quadratic equation = -5 , -4
We have to take out the middle term of quadratic equation , and we know that quadratic equation is in the form of
= ax^2 + bx + c , we have to take out ' b ' .
➡ ( x + 5 )( x + 4 ) {{ Given roots = ( -5 , -4 ) }}
➡ x^2 + 9x + 20 .
♦ Middle Term = 9 .
Hope It Helps You ^_^
Given in the question :
➡ Roots of the quadratic equation = -5 , -4
We have to take out the middle term of quadratic equation , and we know that quadratic equation is in the form of
= ax^2 + bx + c , we have to take out ' b ' .
➡ ( x + 5 )( x + 4 ) {{ Given roots = ( -5 , -4 ) }}
➡ x^2 + 9x + 20 .
♦ Middle Term = 9 .
Hope It Helps You ^_^
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