Chemistry, asked by Anonymous, 8 months ago

What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?​

Answers

Answered by Anonymous
36

P₁ = 1

P₂ = ?

V₁= 500 dm³

V₂= 200 dm³

Apply boyle's law p₁V₁ = p₂V₂ to calculate p₂ as temperature remains constant.

p₂ = p₁V₁ / V₂

= 1 bar × 500 dm³/ 200 dm³

= 2.5 bar

2.5 is the required answer.

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@ ANUSHA

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