Chemistry, asked by Anonymous, 10 months ago

What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?​

Answers

Answered by Anonymous
1

Answer:

2.5 bar

Explanation:

let P2 be the pressure required to compress the gas. Therefore, the minimum pressure required is 2.5 hence done!!

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
26

\huge\sf\pink{Answer}

\sf P_2 = 2.5 \ bar

\rule{110}1

\huge\sf\blue{Given}

\sf P_1 = 1 \ bar

\sf V_1 = 500 \ Dm^3

\sf V_2 = 200 Dm^3

\rule{110}1

\huge\sf\gray{To \:Find}

◈ The Pressure required?

\rule{110}1

\huge\sf\purple{Steps}

Here we know that,

\sf\quad\sf P_1 = 1 \ bar

\sf\quad\sf V_1 = 500 \ Dm^3

\sf\quad\sf V_2 = 200 \ Dm^3

So no was per the ok my Boyles law,at constant temperature,

\underline{\boxed{\sf P_1V_1 = P_2V_2}}

Substituting the given values,

\sf 1 \times 500 = P_2 \times 200

\sf 500 = P_2 \times 200

\sf \dfrac{500}{200} = P_2

\sf\orange{P_2 = 2.5 \ bar}

\rule{140}{1.5}

\large\bullet\:\underline{\red{\sf Boyle's \ law}}

»» The volumes of given mass of a gas is inversely proportional to its pressure exerted (at a constant temperature)

»» \sf V\propto \dfrac{1}{P}

»» \sf V = \dfrac{K}{P}

»» \sf PV = K(constant)

The product of the volume and the pressure of a mass of gas is constant at constant temperature

\rule{170}3

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