what will be the minimum pressure required to compress 500 dmcube of a to 200 dm3 at 1 bar at 30 degree Celsius
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Answered by
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Volume of gas(V1) = 500dm3 (given)
Pressure of gas (p1) = 1 bar (given)
Volume of compressed gas (V2) = 200dm3 (given)
Now ,let P2 be the pressure required to compress the gas.
Therefore at constant temperature P1 V1 = P2 V2(Boyle’s Law)
As a result P2 = P1 V1 / V2 = 1 X 500/200 = 2.5 bar
Therefore, the minimum pressure required is 2.5 bar.
Pressure of gas (p1) = 1 bar (given)
Volume of compressed gas (V2) = 200dm3 (given)
Now ,let P2 be the pressure required to compress the gas.
Therefore at constant temperature P1 V1 = P2 V2(Boyle’s Law)
As a result P2 = P1 V1 / V2 = 1 X 500/200 = 2.5 bar
Therefore, the minimum pressure required is 2.5 bar.
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Answered by
6
Answer:
The pressure will be 2.5 bar.
Explanation:
Referred to the attachment.
Attachments:
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