Question

What will be the minimum pressure required to compress 500 dm cube of air at 1 bar to 200 dm cube at 30° C ?

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Answer 1

Answer:

According to ideal gas equation, P1V1=P2V2

Here P1=1bar,V1=500dm3,V2=200dm3

Then P2=2001×500=2.5bar 

Explanation:

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Answer 2

Answer:

Here is your answer,

P₁ = 1  

P₂ = ?

V₁= 500 dm³

V₂= 200 dm³

Apply boyle's law  p₁V₁=p₂V₂ to calculate p₂ as temperature remains constant.  

p₂ = p₁V₁/ V₂ = 1 bar × 500 dm³/ 200 dm³ = 2.5 bar  

2.5 is the required answer !  

I hope this is helpful!