Question

What will be the minimum pressure required to compress 500 dm³ of air at 5 bar to 200 dm³ at 25°C.​

Answer 1

Answer:According to ideal gas equation, P

1

​

V

1

​

=P

2

​

V

2

​

Here P

1

​

=1bar,V

1

​

=500dm

3

,V

2

​

=200dm

3

Then P

2

​

=

200

1×500

​

=2.5bar

Explanation:

Answer 2

ANSWER: 2.5bar

Explanation

P₁ = 1

P₂ = ?

V₁= 500 dm³

V₂= 200 dm³

Apply boyle's law p₁V₁=p₂V₂ to calculate p₂ as temperature remains constant.

p₂ = p₁V₁/ V₂ = 1 bar × 500 dm³/ 200 dm³ = 2.5 bar

2.5 is the required answer !

----------------------------------------------------------------------------------

HAVE A GREAT DAY ☺️