what will be the molality of a solution when 63 gram HNO3 is dissolved in 750 gram of water
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Moles of HNO₃ = 63 g / (63 g/mol) = 1 mol
Molality = Moles of solute / Mass of Solvent in kg
= 1 mol / (750 × 10^-3 kg)
= 1000/750 molal
= 4/3 molal
= 1.33 molal
Molality of solution is 1.33 m
Molality = Moles of solute / Mass of Solvent in kg
= 1 mol / (750 × 10^-3 kg)
= 1000/750 molal
= 4/3 molal
= 1.33 molal
Molality of solution is 1.33 m
rohan85:
hello friend but my answer is coming 1.333 instead of 13.33
because by dividing 1000÷750 it comes 1.333
Yes. You're right. I'll edit my answer soon.
Answer edited ✅
Thanks for answering.
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