what will be the molality of solution made by dissolving 10g of NaOH in 100g of water?
Answers
Answer:
Answer. Explanation: Molarity of a solution is defined as the number of moles of solutedissolved per Liter of the solution. Therefore, the molarity of solution will be 0.25 mole/L.
Given: A solution made by dissolving 10g of NaOH in 100 g of water
To find: Molality of the solution
Explanation: Molality of a solution is a way of measuring concentration of the solution. Its unit is m.
Molality= Moles of solute/ Mass of solvent in kg
Molar mass of NaOH= 40 g/mol
Mass of water= 100g = 0.1 kg
Now, Moles of NaOH= Given mass/ Molar mass
= 10/40
= 0.25 moles
Using formula of molality given:
Molality= 0.25/0.1
= 2.5 m
Therefore, the molality of solution made by dissolving 10 g NaOH in 100g water is 2.5 m.