Question

what will be the molality of the solution containing 18.25 g of HCl gas in 500 g of water ?

Answer 1

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Answer 2

The molality of the solution is 1 molal.

Given:

$HCl = 18.25 \ gm$

$\mathrm{H}_{2} \mathrm{O} = 500 \ gm$

Solution:

Molality can be defined as the "number of moles" of solute per kilogram of a solvent. In other words, it is the concentration of a solute in a solution.

$\bold{\mathrm{Molality =\frac{\text { "Number of moles" of solute }}{\text { "Number of moles" of solution }} \times 1000}}$

We also know that, the molecular weight of HCl = 36.5

So, the "number of moles" of solute $=\frac{18.25}{36.5}=\frac{1}{2}=0.5$

Now, to calculate molality, we use the above equation,

$\mathrm{Molality=\frac{0.5}{500} \times 1000=1 \ Molal}$