Question

what will be the molality of the solution containing 18.25g of hcl in 50g of water??​

Answer 1

Answer:

The molality of the solution is 1 molal.

Given:

HCl = 18.25 \ gmHCl=18.25 gm

\mathrm{H}_{2} \mathrm{O} = 500 \ gmH

2

O=500 gm

Solution:

Molality can be defined as the "number of moles" of solute per kilogram of a solvent. In other words, it is the concentration of a solute in a solution.

\bold{\mathrm{Molality =\frac{\text { "Number of moles" of solute }}{\text { "Number of moles" of solution }} \times 1000}}Molality=

"Number of moles" of solution

"Number of moles" of solute

×1000

We also know that, the molecular weight of HCl = 36.5

So, the "number of moles" of solute =\frac{18.25}{36.5}=\frac{1}{2}=0.5=

36.5

18.25

=

2

1

=0.5

Now, to calculate molality, we use the above equation,

\mathrm{Molality=\frac{0.5}{500} \times 1000=1 \ Molal}Molality=

500

0.5

×1000=1 Molal