Question

What will be the molality of the solution containing 18.25g of HCL gas in500g of water

Answer 1

Answer:

1

Explanation:

Molar mass of solute HCl is 36.5 gm/mol.

Molality(m) = (mass of solute × 1000 )/{ (molar mass of solute) × (weight of solvent in gm) }.

m = (18.25 × 1000) / (36.5 × 500)

= 18250 /1850

= 1 m.

Answer 2

Answer:

(d) Molality, \[m=\frac{{{w}_{B}}\times 1000}{{{m}_{B}}\times {{w}_{A}}}\] \[{{w}_{B}}=18.25g,\,\,\,\,{{m}_{B}}=36.5g\,mo{{l}^{-1}}\,,\,\,\,\,\,\,{{w}_{A}}=500g\] \[\therefore \] \[m=\frac{18.25\times 1000}{36.5\times 500}=1\]