What will be the molality of the solution obtained by dissolving 9.8 g H2SO4 in 250 g of water
Answers
Answered by
0
Answer:
The Molality is 0.4 moles/kg
Explanation:
Molar Mass of H2SO4 = 98g
No. of moles of H2SO4 in 9.8g is = 9.8/98 = 0.1 moles
molality=number of molesof solute/solvent mass in kg
Molality = 0.1/0.250 = 10/25 = 0.4 moles/kg
Similar questions