What will be the molarity of a solution containing
5g of sodium hydroxide in 250 ml solution
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Explanation:
1 mol NAOH = atomic mass of na + atomic mass of O + atomic mass of H =23+16+1 =40g.
5g of NAOH= 5/40 mol
NaoH=0.125 mol of naoh
250 ml solution= 250/1000 =0.25 L
Now,molarity= no. of moles of solute/total volume of the solvent
0.125/0.25=0.5 mol/L
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