What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?
Answers
Answer:
0.2 mol LX-1
Step-by-step explanation:
Given:
Quantity of NaCl per 500 ml = 5.85 grams
Converting 500 ml to litre by dividing by 1000:
= 0.5 Litre
To Find:
Molarity of the solution
Formula used to find the molarity of a solution:
M = No of moles of solute / Volume of solution in Litres
Calculating the Molar Mass of NaCl:
= 1 x 23 + 1 x 35.5
= 23 + 35.5
= 58.5
Calculating the moles of solute in the solution:
= Weight / Molar Mass
= 5.85 / 58.5
= 0.1 mol
Calculating the molarity of the solution by substituting the values we know into the formula mentioned above:
M = No of moles of solute / Volume of solution in Litres
= 0.1 / 0.5
= = 0.2 mol L^-1
Therefore, 0.2 mol L^-1 will be the molarity of the solution which contains 5.85 grams of NaCl per 500 ml.
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Answer:
Molarity, M= number of moles/volume of solution
M= n/V
Number of moles, n= mass/molar mass
Molar mass of NaCl=58.5 g/mol
Mass = 5.85g
n=5.85/58.5=0.1 mol
Volume, V=500 mL=0.5 L
∴M=0.1/0.5=0.2mol/L