Question

What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?​

Answer 1

Answer:

Therefore, 0.2 mol L^-1 will be the molarity of the solution which contains 5.85 grams of NaCl per 500 ml.

Answer 2

weight=Molarity*Molecular Mass * volume/1000

weight*1000/Molecular mass*volume

In letters

w'=M*M'*v/1000

here w' is weight ,M is molarity M' = Molecular mass of Nacl and v is for volume

M=?,v=500ml,w'=5.85g and M'=NaCl=23+35=58

putting values Molarity=weight*1000/Molecular mass * volume

M=5.85*1000/58*500

calculating

0.20 is the molarity