Question

What will be the molarity of a solution,
which contains s.859. of NaCl (s) per 500 ml​

Answer 1

Answer:

Explanation:

859/mwt of nacl(i.e. 58.5)

moles of NaCl =14.6

molarity=14.6*1000/500     (multiplied by 1000 becz volume should be inn the litres)

M=29.2

Answer 2

Answer Text

`"4 mol L"^(-1)`

`"20 mol L"^(-1)`

`"0.2 mol L"^(-1)`

`"2 mol L"^(-1)`

Answer :

C

Solution :

Molarity (M) `= (("5.85 g")//("58.5 g mol"^(-1)))/("(500/1000)L")`

`=(0.1)/(0.5)=0.2 "mol L"^(-1)`