Question

what will be the molarity of the solution in which 0.365g of HCL gas dissolve in 100mlof solution
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Answer 1

Molarity=$$\dfrac{number of moles}{volume(L)}$$

and number of moles=\dfrac{mass}{molar\ mass}

molar mass

mass

For HCl, mass=0.365g, molar mass=36.5 g/mol and volume=100mL=0.1 L

Thus, molarity=\cfrac{0.365}{36.5 \times 0.1}=0.1 M

36.5×0.1

0.365

=0.1M

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Answer 2

Answer:

molarity=0.365×10^-3/100×10^-3

=0.00365M

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