What will be the momentum of the body of mass 13kg which is moving with a velocity 0.5ms-1?
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Answer:
Hope this helps you
Explanation:
Mass (m) = 5 Kg
Momentum (p) = 10 Kg m/s
Force applied (F)= 0.2N for t= 10 seconds
Solution:
Momentum (p)=m∗u=10Kgm/s
(Here u is the velocity at which the object is moving)
p=5∗u=10
u=105=2m/s
F=m∗a=0.2N
( When force is applied to the moving object then object will accelerate at 'a')
F=5∗a=0.2
a=0.25=0.04m∗s−2
Now, using Newton's laws of motion we will find the new velocity (v) of the object
v=u+a∗t
v=2+0.04∗10=2.4m∗s−1
Change in kinetic energy is
ΔK.E=12m∗v2−12m∗u2
ΔK.E=12∗m(v2−u2)
ΔK.E=12∗5∗(2.42−22)
ΔK.E=0.5∗5∗(5.76−4)=4.4J
Increase in kinetic energy will be 4.4 joules.
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