what will be the mutual inductance of two coils when the change of a current of 3 ampere in one coil produces the change of flux of 6×10-4 weber in the second coil having 2000 turns?
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Answer:
given I=10A
t=0.5A
ϕ=500wb/turn
N=200
total flux =500×2 =10
5
wb
mutual inductance =r
2
induced emf e=?
Q=MI
m=
I
Q
=
10
10
5
m=10
4
H
e=
dt
mdI
=
0.5
10
5
×10
e=2×10
6
V
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