What will be the nature of motion if the displacement time graph looks like the above picture:
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(a). slope is constant so
x/t = const.
v = const.
the particle is moving uniform motion
(b) slope is decreasing so there is negative acceleration.
so the motion is uniform retardation motion
please follow me
x/t = const.
v = const.
the particle is moving uniform motion
(b) slope is decreasing so there is negative acceleration.
so the motion is uniform retardation motion
please follow me
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