what will be the nature of roots of the equation X square - 3 X = 24 also find the roots if exist
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Step-by-step explanation:
x^2-3x-24=0
b^2-4ac
105
therefore it has real roots
x=-b+rootb^2-4ac/2a,-b-rootb^2-4ac/2a
=-3+root105/2,-3-root105/2
Hope its correct <3
shams25:
thanks
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