Question

What will be the no. of electrons removed from a body in order to produce a positive charge of
$48 \times {10}^{ - 20}$
on it?​

Answer 1

As we know that,

Q = ne

where Q = charge

n = number of ekectron removed

e = 1.6 × 10^-19

48 × 10^-20 = n × 1.6 × 10^-19

n = 3

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