Question

What will be the normality of a solution obtained by mixing 0.45 normality and 0.60 Normality NaOH in the ratio 2 :1 by volume

Answer 1

Normality of resulting solution= N1V1+N2V2/V1+V2

               Since V1/V2=1/2 = V2=2V1(substituting it in the above given equation)

N1=0.45 N, V1=V1  ; N2=0.60,V2=2V1.

  Now,  0.45*V1+0.60*2V1/V1+2V1

       =      0.45V1+1.20V1/3V1

        = 1.65 V1/3V1       (V1 gets cancelled)

        =0.55 N

Answer 2

Answer: The normality of the resulting solution is 0.5 N

Explanation:

To calculate the normality of the solution after mixing 2 solutions, we use the equation:

$N=\frac{N_1V_1+N_2V_2}{V_1+V_2}$

where,

$N_1\text{ and }V_1$ are the normality and volume of the solution 1.

$N_2\text{ and }V_2$ are the normality and volume of the solution 2.

We are given:

$N_1=0.45N\\N_2=0.60N$

$\frac{V_1}{V_2}=\frac{2}{1}\\\\V_1=2V_2$

Putting all the values in above equation, we get:

$N=\frac{0.45(2V_2)+0.60(V_2)}{(2V_2)+V_2}\\\\N=\frac{0.9V_2+0.6V_2}{3V_2}\\\\N=\frac{1.5V_2}{3V_2}\\\\N=0.5N$

Hence, the normality of the resulting solution is 0.5 N