what will be the number of bivalents in meiotic stage in meiocytic has 40 chromosomes
Answers
Hey mate here ur answer,
Maize has chromosome number is 20(2n).
In pachytene stage, a tetrad of the chromosomes has formed known as a bivalent. This is the stage when homologous recombination, including chromosomal crossover, occurs. The DNA molecule is packaged into thread-like structures called chromosomes. A bivalent sometimes referred to as a tetrad, is the association of a pair of homologous chromosomes physically held together by at least one DNA crossover. This physical attachment allows for alignment and segregation of the homologous chromosomes in the first meiotic division. Telomeres are the caps at the end of each strand of DNA that protect our chromosomes, like the plastic tips at the end of shoelaces.
So, in maize, the number of bivalent and tetrad is 20,
Each chromatid has 1 DNA so in 40 chromatids DNA is 20*2=40,
Each DNA has 2 telomers so Telomeres is 40*2=80
Correct answer is “20,20,40,80”.
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Answer:
The number of bivalents in meiotic stage in meiosis of a cell having 40 chromosomes will be 20.
Explanation:
- Meiosis is the reductional cell division where the first there are 2 divisions of the nucleus and a single cytokinesis.
- Thus, the first division occurs between pairs of a chromosomes with one of each pair going to the opposite pole rather than between the chromatids of a chromosome (this happens at the second meiotic division).
- These chromosome pairs, that in return hail from both the parents of the offspring, are known as bivalents.
- Therefore the pairing up of 40 chromosomes will create 20 bivalents.
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