Math, asked by Anonymous, 1 year ago

What will be the number of faces of a polyhedron having 6 vertices and 9 edges.

Answers

Answered by Anonymous
32
Heya..

Given :

Vertices = 6

Edges = 9

Let no of faces be F.

According to Euler's law:

F+ V - E = 2

=) F + 6 - 9 =2

=) F - 3 = 2

=) F = 5

Hope it's helpful to u.

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Answered by karunabanerjee91
3

Answer:

5 faces

Step-by-step explanation:

according to Euler's formula

faces + vertices - edges =2

so faces + 6 - 9=2

faces =2-6+9

faces=5

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