What will be the number of faces of a polyhedron having 6 vertices and 9 edges.
Answers
Answered by
32
Heya..
Given :
Vertices = 6
Edges = 9
Let no of faces be F.
According to Euler's law:
F+ V - E = 2
=) F + 6 - 9 =2
=) F - 3 = 2
=) F = 5
Hope it's helpful to u.
Given :
Vertices = 6
Edges = 9
Let no of faces be F.
According to Euler's law:
F+ V - E = 2
=) F + 6 - 9 =2
=) F - 3 = 2
=) F = 5
Hope it's helpful to u.
Anonymous:
Thanks
Answered by
3
Answer:
5 faces
Step-by-step explanation:
according to Euler's formula
faces + vertices - edges =2
so faces + 6 - 9=2
faces =2-6+9
faces=5
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