What will be the number of nitrogenous bases in chromatin fibre containing 936 histones?
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Explanation:
a nucleosome have 200bp and 9 histone proteins(octamer+H1 protein)
•°•,
no of nucleosomes = no of histone protein÷no of histone protein in 1
nucleosome(9)
= 936 / 9 = 104 nucleosomes
•°•,
no of bp = no of nucleosomes × 200
= 104×200
= 20800 bp
•°•,
no of nitrogenous bases = no of bp × 2 = 20800 × 2 = 41600 bases
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