Question

what will be the number of product in the given reaction C6H5-CHO+CH3-CHO+NaOH product option 1,2,3,4​

Answer 1

(4) Four

Given rection:

• C6H5-CHO+CH3-CHO  ------- NaOH -------- >  

To Find:

• The Products of the reaction.

Solution:

• The Aldol Condensation can be defined as the organic reaction in which an enolate ion reacts with the carbonyl compound to form β-hydroxy ketone or the β-hydroxy aldehyde, followed by the dehydration to give, conjugated enone. Aldol Condensation plays the vital role in the organic synthesis, creating the new paths to form the Carbon - - Carbon bonds.

Thus the products are :

(1) OHC-HC=CH-CH3  

(2) CH3-CH=CH-CH2-CHO  

(3) H2C=CH-CH=CHO  

                       |

                     CH3

(4) CH3-CH=CH-CH-CHO

                             |

                          CH3

C6H5-CHO+CH3-CHO+ NaOH ------------------------ >  

(OHC-HC=CH-CH3  

CH3-CH=CH-CH2-CHO  

H2C=CH-CH=CHO  

                 |

               CH3

CH3-CH=CH-CH-CHO

                       |

                     CH3

Hence the answer is 4 products.

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Answer 2

Answer:

Only one product will be formed when C₆H₅CHO + CH₃CHO reacts in the presence of NaOH.

Explanation:

Given,

The reactants C₆H₅CHO + CH₃CHO + NaOH

To find,

The number of products formed by the reaction of the above reactants.

Calculation,

Cross aldol condensation:

Crossed aldol condensation is a variation of aldol condensation in which two dissimilar carbonyl compounds (each containing alpha hydrogens) undergo the condensation reaction together. In such reactions, up to four different products may be formed.

Now when C₆H₅CHO + CH₃CHO reacts in the presence of NaOH, we get:

C₆H₅CH₂OCH₂CHO as the only product.

Therefore, only one product will be formed when C₆H₅CHO + CH₃CHO reacts in the presence of NaOH.

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