what will be the number of real zero of the polynomial x²+1
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➡HERE IS YOUR ANSWER⬇
In this problem, the polynomial (x²+1) has no real roots.
Reason :
x²+1
= x² - i², where i is the imaginary value of root over (-1) => i = root ovee (-1)
= (x + i) (x - i)
So, the zeroes of the given polynomial (x²+1) are -i and i.
⬆HOPE THIS HELPS YOU⬅
In this problem, the polynomial (x²+1) has no real roots.
Reason :
x²+1
= x² - i², where i is the imaginary value of root over (-1) => i = root ovee (-1)
= (x + i) (x - i)
So, the zeroes of the given polynomial (x²+1) are -i and i.
⬆HOPE THIS HELPS YOU⬅
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