Math, asked by tarwarmeetkaur, 1 year ago

what will be the number of real zero of the polynomial x²+1

Answers

Answered by Swarup1998
0
➡HERE IS YOUR ANSWER⬇

In this problem, the polynomial (x²+1) has no real roots.

Reason :

x²+1

= x² - i², where i is the imaginary value of root over (-1) => i = root ovee (-1)

= (x + i) (x - i)

So, the zeroes of the given polynomial (x²+1) are -i and i.

⬆HOPE THIS HELPS YOU⬅
Similar questions