What will be the number of real zero of the polynomial x²+1
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SOLUTION::-
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p(x) = x^2+1
x=-b± (b^2-4ac/2a)1/2
given ,
a=1
b=0
c=1
x=0 ± (0-4/2(1))1/2
=0±(-4/2)1/2
=±2i/2
= +i or -i
i is a complex number not i ∉R
x^2+1 has no real zero
____________________________________
p(x) = x^2+1
x=-b± (b^2-4ac/2a)1/2
given ,
a=1
b=0
c=1
x=0 ± (0-4/2(1))1/2
=0±(-4/2)1/2
=±2i/2
= +i or -i
i is a complex number not i ∉R
x^2+1 has no real zero
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