Question

What will be the number of real zeroes of the polynomial x^2+1 ?

Answer 1

Answer:

We have,

Given polynomial is

x

2

+1=0

So,

x

2

+0x+1=0

On comparing that,

Ax

2

+Bx+Cx=0

Now,

A=1,B=0,C=1

Using quadratic formula,

x=

2A

−B±

B

2

−4AC

x=

2×1

−0±

0

2

−4×1×1

x=

2

−4

x=±

2

2i

x=±i

It is complax number

So, it has no real roots.

Hence, this is the answer