Question

what will be the number of real zeroes of the polynomial x² + 1

Answer 1

0, because its discriminant will be 2i, which is an imaginary number.

Answer 2

Heya !!!

Here is Your answer.

Given :
x² + 1

Comparing with ax² + bx + c = 0, we get
a = 1, b = 0 and c = 1.

Discrimanant = b² - 4ac
= - 4

As D < 0, So it does not have any real root..

Hope It Helps