Question

What will be the output if limit = 6?
Read limit
n1 = 0, n2= 1, n3=1, count = 1;
while count <= limit
count=count+1
print n3
n3 = n1 + n2
n1 = n2
n2 = n3
End While​

Answer 1

Output is

1

1

2

3

5

8

Thats a fibo

Answer 2

Answer:

The final output will be : 1 1 2 3 4 5.

Explanation:

while (count <= limit)

Here, limit is 6.

count=count+1;

The count will increase and simultaneously.

for count = 1

first " 1 " will be printed.

Then

n3= n1 + n2

n3 = 0 + 1   ⇒ n3 = 1

n1 = n2       ⇒ n1 = 1

n2 = n3      ⇒ n2 = 1

for count =2

first " 1 " will be printed.

Then  

n3 = n1 + n2 ⇒ n3 =2

n1 = n2         ⇒ n1 = 1

n2 = n3       ⇒ n2 = 2

for count =3

first " 2 " will be printed.

Then  

n3 = n1 + n2 ⇒ n3 =3

n1 = n2         ⇒ n1 = 2

n2 = n3       ⇒ n2 = 3

Similarly, following the pattern for count = limit = 6

first " 5 " will be printed.

Then  

n3 = n1 + n2 ⇒ n3 =6

n1 = n2         ⇒ n1 = 5

n2 = n3       ⇒ n2 = 6

Hence, the final printing output will be

1 1 2 3 4 5.

#SPJ3

25 MAY 2022.