Question

What will be the output of the following code?
int i=20;
if(i>10)
{ System.out.println( "The value of i is "+i);
i++;
if(i%2!=0)
break; }

Answer 1

Explanation:

$\huge\underline\green{Hey\:here\:is\:your\:answer..}$

$<marquee>the value of i is 20$

$<marquee>Thank You$

Answer 2

We need to find the output of the given code.

Let's observe the code.

The first line of the code is

int i= 20;

Here in this line we have defined an integer i and assigned it to the value 20

Now, the value of i is 20.

if(i>20)

{

System.out.println ("The value of i is "+i")

i++

if(i%2 !=0)

break;

}

In this code, we enter the if block only when the value of i>20. The value of i is 10. So we enter the if block.

Then we have System.out.println(" The value of i is "+i")

This statement prints the value of i in the output.

Then the line i++ increments the value of i. Now the value of i will be i+1 that is 11.

Value of i is 11.

The line if(i%2 !=0)

if(i%2 !=0) break

We enter this if block only when i/2 doesn't gives us the remainder zero.

The value of i is 11. When we divide 11 by 2 we get remainder of 1. 1!=0. Hence, we enter the if block. If block contains break. Then we come out of the block.

Finally the output is

The value of i is 20

#SPJ2