Question

What will be the output of the following program?
#include<stdio.h>
#define prod(a,b) a*b
void main()
{
int x=3 y=4;
printf("%d", prod(x+2,y-1));
}
015
010
0 12
11
None of these​

Answer 1

Answer:

010 will be the answer

Explanation:

The code compile as follows

Here you used the preprocessor in the program

So the code will be substitute preprocessor code when it encounter the preprocessor name

=>we have passed x+2 and y-1 in the preprocessor function

The code of preprocessor is a*b

So the x+2 and y-1 will be treated as an equation as

x+2*y-1

Here x and y values are 3, 4 reapectively

So=>

3+2*4-1

Accoeding to the operators precedence /, *, +, - will be performed in order

=>3+8-1

=>11-1

=>10 so the output will be 10

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