Question

What will be the output of the program?
#include
int main()
{
typedef int LONG
LONG a=4
LONG b=68:
float c=0;
c=b;
bu-a,
printf("%d", b);
printf("96110c);
return 0

Answer 1

Answer:

please post correct question

Answer 2

Explanation:

B. 2, 3, 20

C. 2, 1, 15

D. 1, 2, 5

Answer: Option A

Solution(By Examveda Team)

>> int a[5] = {5, 1, 15, 20, 25}; The variable arr is declared as an integer array with a size of 5 and it is initialized to

a[0] = 5, a[1] = 1, a[2] = 15, a[3] = 20, a[4] = 25.

>> int i, j, m; The variable i, j, m are declared as an integer type.

>> i = ++a[1]; becomes i = ++1; Hence i = 2 and a[1] = 2

>> j = a[1]++; becomes j = 2++; Hence j = 2 and a[1] = 3.

>> m = a[i++]; becomes m = a[2]; Hence m = 15 and i is incremented by 1(i++ means 2++ so i=3)

>> printf("%d, %d, %d", i, j, m); It prints the value of the variables i, j, m

Hence the output of the program is 3, 2, 15.