Question

What will be the output of this program on an implementation where int occupies 2 bytes?

#include void main() { int i = 3; int j; j = sizeof(++i + ++i); printf("i=%d j=%d", i, j); }
A.i=4 j=2
B.i=3 j=2
C.i=5 j=2
D.the behavior is undefined

Answer 1

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option a is the correct answer

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Answer 2

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QUESTION:

What will be the output of this program on an implementation where int occupies 2 bytes?

#include void main() { int i = 3; int j; j = sizeof(++i + ++i); printf("i=%d j=%d", i, j); }
A.i=4 j=2
B.i=3 j=2
C.i=5 j=2
D.the behavior is undefined

ANSWER:

Option 【A】i=4 j=2

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