what will be the partial pressure of h2 in a flask containing 2 g of h2, 14g of n2 and 16g of o2
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Answered by
6
Partial pressure of gas in mixture = mole fraction of gas x pure pressure
mole fraction of gas = moles of gas/total number of moles of gas in mixture
At first we will calculate the moles of each gas and then total number of moles
Moles of H2 = given mass/Molar mass
= 2 g/2 g mol-1
= 1mol
Moles of SO2 = 32 g/64 g mol-1
= 0.5 mol
Total number of moles = 1 + 0.5 = 1.5 moles.
Mole fraction of H2 = 1/1.5 = 0.67
Mole fraction of SO2 = 0.5/1.5 = 0.33
Let the Pure pressure is 1 atm (not given hence assuming)
Then partial pressure of H2 = 0.67 x 1 atm = 0.67 atm
Partial pressure of SO2 = 0.33 x 1 atm = 0.33 atm
mole fraction of gas = moles of gas/total number of moles of gas in mixture
At first we will calculate the moles of each gas and then total number of moles
Moles of H2 = given mass/Molar mass
= 2 g/2 g mol-1
= 1mol
Moles of SO2 = 32 g/64 g mol-1
= 0.5 mol
Total number of moles = 1 + 0.5 = 1.5 moles.
Mole fraction of H2 = 1/1.5 = 0.67
Mole fraction of SO2 = 0.5/1.5 = 0.33
Let the Pure pressure is 1 atm (not given hence assuming)
Then partial pressure of H2 = 0.67 x 1 atm = 0.67 atm
Partial pressure of SO2 = 0.33 x 1 atm = 0.33 atm
kabir89:
my question is different ,
Answered by
17
Partial pressure is always proportional to or you can say equal to the mole fraction as PP is a ratio and in a ratio proportionality constant gets cancelled.
There fore, moles of H2 here is 1, moles of N2 here is 0.5 and moles of O2 here is 0.5.
Thus, the Partial presure of H2 = 1/(1+0.5+0.5) = 1/2=0.5
Inform if wrong. Approve if correct.
Yeah Yeah, Partial pressure is the total pressure that a certain molecule has from the total pressure.
You know this formula, PV=NRT?
Here, when Volume, temperature, and Pressure are constant, P is proportional to N.
There fore if we assume P1, P2 and P3 to be the partial pressure, and N1, N2 and N3 to be the moles
(P1+P2+P3)= k (N1+N2+N3).
(P1+P2+P3)= k (N1+N2+N3).
And writing indiviual results,
P1= kN1
P2=kN2
P3=kN3
Here we are assume gas 1 to be H2, gas 2 to be N2 and gas 3 to be O2.
Thus partial pressure of H2= P1/(P1+P2+P3)=kN1 / k(N1 + N2 +N3)
Thus as I said, the k gets cancelled and we are left with the mole fraction of H2 which is 0.5.
P1= kN1
P2=kN2
P3=kN3
Here we are assume gas 1 to be H2, gas 2 to be N2 and gas 3 to be O2.
Thus partial pressure of H2= P1/(P1+P2+P3)=kN1 / k(N1 + N2 +N3)
Thus as I said, the k gets cancelled and we are left with the mole fraction of H2 which is 0.5.
That's the whole legit solution.
ohhkk
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