What will be the path of a charged particle projected along a magnetic field
Answers
If the field is in a vacuum, the magnetic field is the dominant factor determining the motion. Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle.
Answer:
If we assume that the charge was traveling linearly from the beginning, it will continue to flow in this same direction with no variation.
Explanation:
To find:
The Path over charged particle projected on the flux?
Calculation:
The general expression of force fully fledged by a moving charge particle is given as :
\therefore \: \vec = q( \vec \times \vec)∴
F
=q( v × B )
{\implies \: | \vec | = alphabetic character \times v \times B \times \sin( \theta) }}
⟹ F
=q×v×B×sin(θ)
Here "F" is force, "q" is charge, "v" is rate, "B" is flux intensity and \thetaθ is the angle between the rate vector and field strength vector.
When the charged particle is moving in the direction of flux intensity, we are able to say that \theta = ^θ=0
Putting the on the market values:
\implies \: | \vec| = alphabetic character \times v \times B \times \sin( ^ )⟹∣
F
=q×v×B×sin(0∘)
\implies\: | \vec| = zero \: N⟹∣
F
=0N
So, the moving charged particle doesn't expertise any force.
Hence, if we tend to contemplate that the charge was ab initio moving linearly, then it'll still move in this same direction with no deviation.
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